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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Dec 2006 15:14:30 IST
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what is the value of "1/i" ?
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17 Dec 2006 15:18:52 IST
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SOLUTION - WE HAVE,
1/ i = i2/ i3
on solving ,
1/ i = -i
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17 Dec 2006 15:21:40 IST
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Yes ur answer is absolutely correct ... 1/i is indeed -i cheers
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Puneet Agrawal
IIT Delhi
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19 Dec 2006 22:12:36 IST
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1/i x -i/-i (multipling by conjugate) we get,, -1/-i² = -1/-1 = 1 that s it .. IS IT RIGHT ??
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DREAM TOWARDS YOUR GOAL THAT WILL LEAD YOU TO SUCCESS. |
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20 Dec 2006 13:47:46 IST
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Hey,
Abhiabhijain
your ans is correct.
Plz tell me why
how can you have i2 in the numerator and i3 in the denominator in the equation-----1/i=i2/i3
Plz explain me elaborately.
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20 Dec 2006 14:22:36 IST
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your q is not clear
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20 Dec 2006 14:47:18 IST
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Every complex no. is best treated if converted in polar form so, 1/i=1/[e^i(pie)/2] so, 1/i=e^-i(pie)/2 so, 1/i=cos(pie/2)-isin(pie/2) s0,1/i=-i multipling by conjugates and getting ans. 1 is somethin' tricky but even by De Moivre's th. ans=-i
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