If 3sin[ pi/12 + x] = cos[pi/12 - x]

Prove: sin2x = 1/7

first of all

3sin(15+x)=cos(15+x)

by using sin(A+B) nd cos(A+B)



we get the terms in sinx nd cosx nd remember to use sin15

we get 3(root3-3)cosx-(root3+1)cosx=(root3-1)sinx-3(root3+1)sinx...

i m unable to give further steps coz large eq...i gave you the intermediate step which is useful.....by further solving we get tanx...so now it is easy to find sin2x...



RATE ME IF MY ANS IS SATISFACTORY...

sin15=(root3-1)/2root2

nd cos15=(root+1)/2root2