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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Sep 2008 20:24:57 IST
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which of the following has the maximum and minimum bond dissociation energy?
F2 , Cl2 , Br2 AND I2
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19 Sep 2008 20:35:18 IST
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min -F2
max- Cl2
this is because of large electron-electron repulsion among the lone pairs in F2 molecule as compared to Cl2.
so the bond in F2 becomes weak and is easier to break leading to its minimum bond dissociation enthalpy.
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20 Sep 2008 12:23:14 IST
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its not due to repulsion but due to small size of F atom and strong attraction b/w nucleus of one and electrons of other due to less distance between them...
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20 Sep 2008 19:23:30 IST
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1+2 is my answer
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20 Sep 2008 19:36:35 IST
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Cl2 has the maximum and I2 has the minimum. The corect order is Cl2 > F2 > Br2> I2
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20 Sep 2008 19:45:53 IST
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the order will be F2>Cl2>Br2>i2
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20 Sep 2008 20:01:28 IST
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there is electron-electron repulsion b/w the small flourine atoms. that's why b.d.e. for F2 is less than Cl2
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20 Sep 2008 23:07:16 IST
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sahil is right
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21 Sep 2008 15:30:20 IST
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okay okay right... sahil,,,, Cl2 has max and I2 has minimun... the data is given below
F-F Cl-Cl Br-Br I-I
Bond dissociation enthalpy 158 242.6 192.8 151.1
(kJ/mol)
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