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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Sep 2008 21:07:48 IST
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Find out the number of ways in which the word ARRANGE can be arranged such that there is at least one vowel between two consonants.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Sep 2008 21:13:05 IST
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is the ans 5C3*2!...
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IMPOSSIBLES ARE OFTEN UNTRIED... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Sep 2008 21:43:47 IST
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ARRANGE
There are 3 vowels - A,A,E
and 4 consonants - R,R,N,G
The consonants can be arranged in : 4! / 2! ways
Now, in order to arrange in such a manner that there is atleast one vowel between any 2 consonants, in this case we need a vowel between every 2 consonants.
There are 3 such positions.
Therefore, the vowels can be placed in: 3!/2! ways
So the total ways are:
(4! / 2!) * (3! / 2!)
= 36 ways. (edited calculation mistake)
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- Gaurav Ragtah (spideyunlimited)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Sep 2008 22:38:22 IST
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Re:Hey Guys, P&C- try it!
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I like to be myself. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Sep 2008 22:50:06 IST
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@ Rajat sen Your arrangements will also include arrangements such as ARANEGR , ERARENG which have 2 consonants together.
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- Gaurav Ragtah (spideyunlimited)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Sep 2008 22:52:10 IST
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@spideunlimited check your last step 4!/2! * 3!/2! is not equal to 18
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I like to be myself. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Sep 2008 22:55:24 IST
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OH crap, i mistook it as C instead of P...
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- Gaurav Ragtah (spideyunlimited)
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