Parametric equation of normal : y = tx - 2at - at3
y = tx - 4t - 2t3
It oasses through (3,5)
5 = 3t - 4t - 2t3
2t3 + t + 5 = 0
If its roots are p,q,r then p+q+r = 0
Oridnates of feets of normals are given by 2ap,2aq,2ar i.e. 4p,4q,4r
their arithmetic mean = (4p+4q+4r)/3 = (4/3)(o+q+r) = 0