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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Apr 2007 22:00:34 IST
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COMPREHENSION n charges , all of same magnitude are placed at the n corners of a geometrical structure or object (eg.triangle,cuboid,tetrahedron,parallelogram etc.).At the centre of the structure potential is V and the field is E.It should be noted that n is ODD here.Answer the given questions.MORE THAN ONE CORRECT OPTIONS are there. <I> (i) If V=0 then E  0 or may be E=0 (ii) If V=0 then always E=0 (iii)If V=0 then always E 0 (iv) If V0 then always E=0 (v) If V 0 then always E 0 (vi) If V 0 then E=0 or may be E 0 <II> (i)If E=0 then V=0 or may be V 0 (ii)If E=0 then always V=0 (iii)If E=0 then always V 0 (iv)If E then V=0 or may be V 0 (v)If E 0 then always V=0 (vi)If E 0 then always V 0 [ I have given more than 4 options to clear the concept.]
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Ken
From: UNITED STATES, Green Bay, Wisconsin
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27 Apr 2007 16:16:29 IST
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Always use the fact that electric field is negative gradiant of electric potential. or E = -  V = -dV/dx ....(for one dimensional) and E = -dV/dx i - -dV/dy j - -dV/dz k
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The Scientist does not study nature because it is useful; he studies it because he delights in it, & he delights in it because it is beautiful. If nature were not beautiful, it would not be worth knowing, life would not be worth living. Ofcourse I do not here speak of that beauty that strikes the senses, the beauty of qualities & appearances; not that I undervalue such beauty, far from it, but it has nothing to do with science; I mean that profounder beauty which comes from the harmoniuos order of the parts, & which a pure intelligence can grasp. |
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27 Apr 2007 20:31:03 IST
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sir but this law is valid only when we know that field creates a conservative force how do we decide that the eletric field cretaes conservative force or not!!!!i hope u understand wat i mean!!!Do reply sooon
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Life Ka fundaa hai
Jiyo aur jino do |
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27 Apr 2007 20:53:51 IST
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I am sorry but the above explanations are irrelavant to my question .
I just want the correct answer to clear mine and other goiitian's concept.Just tell me the correct options.I have given a geometrical problem based on n as ODD because this involves a tricky concept.
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Ken
From: UNITED STATES, Green Bay, Wisconsin
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2 May 2007 19:53:25 IST
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Hey can no one solve this!!!!!!Then what will happen in IIT JEE 2008.
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Ken
From: UNITED STATES, Green Bay, Wisconsin
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2 May 2007 21:28:19 IST
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hanumaan
field is conservative if it is created due to charges .
INDUCED electric field from magnetic field is non conservative
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khud hi ko kar buland itna ki khuda bhi tujhse puche ...bol bande , teri raza kya hai |
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3 May 2007 13:14:30 IST
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look if we take infinity as o potential then V is not 0 but field is 0
the problem can be solved by basic vector properties
rate the ans plz
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3 May 2007 19:44:59 IST
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Well you are absolutely right robinphilip.And amengem, well try.When n is ODD V can never be zero but E may or may not be zero.
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Ken
From: UNITED STATES, Green Bay, Wisconsin
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