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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Apr 2007 22:34:37 IST
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If radius of capillary is reduced to half, the rise of liquid column becomes ___ times.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Apr 2007 22:42:11 IST
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it bcomes 4 times
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Apr 2007 22:42:26 IST
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h=2Scos$/rdg so when radius is hailved h will become double
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Apr 2007 23:26:37 IST
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h = 2cos /rdg
Hence h 1/r
Hence if radius is halved then capillary rise would be doubled.
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Apr 2007 00:56:12 IST
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h ih inversly proportional to r. so when r is halved then it will become 2 times
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