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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Apr 2007 21:49:54 IST
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The equation of the smallest circle the point of intersection of the line x+y=1 and the circle x2+y2=9 is a. x2+y2+x+y-8=0 b. x2+y2-x-y-8=0 c. x2+y2-x+y-8=0 d. none of these.
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21 Apr 2007 21:58:22 IST
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hey clear out ur ques...
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21 Apr 2007 22:01:10 IST
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the question is over man do u want the options
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21 Apr 2007 22:05:03 IST
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hey read d ques.. its incomplete.. does d circle passes thru d intersection of d line n d givemn circle.../???
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21 Apr 2007 22:08:14 IST
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its b)
x^2 + y^2 -x-y-8 =0
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21 Apr 2007 22:10:26 IST
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give me the solutions man
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21 Apr 2007 22:17:08 IST
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look. x+ y =1
y = 1-x..
put in d circle...
x^2 + (1-x)^2 =9
x^2 - x -4 =0
x=1/2(1+sqrt 17) & 1/2(1- sqrt 17)
for these values of x.. find values of y
Y=1/2(1 - sqrt 17) & 1/2(1+ sqrt 17)
then d pts of intersection come out 2 b
(1/2(1+sqrt 17),1/2(1 - sqrt 17))
and (1/2(1- sqrt 17),1/2(1+ sqrt 17))
nw for d smallest circle dese should be d extremeties of d diameter of d circle....
so =n of circle is
(x-x1)(x-x2) + (y-y1)(y-y2) = 0 (x1,y1) & (x2,y2) extremities of diameter
x^2 + y^2 -x -y -8 = 0
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hey after d hard work i deserve a rate man... lol...
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21 Apr 2007 22:28:26 IST
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ok da
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21 Apr 2007 22:30:15 IST
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u satisfied wid d soln.. if yes... click on d hat for 5 pts(green)..or d hand for 2 pts(grey)..... on d bottom right side of my reply..
lol..
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21 Apr 2007 22:31:35 IST
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thnx dude.... satisfied...??
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21 Apr 2007 22:31:52 IST
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do u have any questions da?
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21 Apr 2007 22:33:05 IST
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how to improve the ratings!
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21 Apr 2007 22:33:53 IST
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matlab??? urs or mine .. lol..
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22 Apr 2007 02:44:00 IST
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The diameter of the smallest circle should lie along x+y=1 and its end points are the intersecti |
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