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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Apr 2007 09:00:23 IST
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C6H5OH+[NH3, ZnCl2, heat] gives A A + CH3COCl gives B B + HNO3+H2SO4 gives C C+ H2O gives D position isomer of D is_______ a)p nitoraniline b)mnitroaniline c)sulphanilic acid d)benezene diazonium chloride explain
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23 Apr 2007 09:23:02 IST
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The answer is (b).
The major products obtained are as follows:-
A - aniline
B - acetanilide
C - p-nitroacetanilide
D - p-nitroaniline
Hence a position isomer of p-nitroaniline is m-nitroaniline.
Hope this helps.
Please rate me.
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23 Apr 2007 09:34:39 IST
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i hav a doubt ,i don think any of the options are right ,first with Zncl2 and NH3 ,u get pheny hydroxyl amine which on heating gets onverted to para amino phenol,if u raect that with acetyl chloride ,u get 4 hydroxy acetanilide ,if u nitrate that u will get 4 hydroxy 3 niro acetanilide, on hydrolysis u get 4 hydoxy 3 niro aniline, its position isomer is not there in the options,hope iam right ,rate me pls
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23 Apr 2007 09:45:23 IST
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Hey,
I think you have forgotten this reaction
PhOH + NH3 --ZnCl2(anhy.), 675K ---> PhNH2 + H2O
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23 Apr 2007 09:47:15 IST
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oh oh ok ok then its absolutely correct dude
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23 Apr 2007 09:49:33 IST
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Sorry to disturb, but how do you get that 'rate the reply' box on the right bottom of the reply box?
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23 Apr 2007 09:50:51 IST
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why u wanna gimme a bad job dude rate huh ,basically i hav no idea
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28 Apr 2007 22:55:53 IST
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9872 C6H5OH + NH3 ® C6H5NH2 (A) aniline C6H5NH2 + CH3COCl ® C6H5NHCOCH3 (B) Acetanilide C6H5NHCOCH3 + HNO3/H2SO4 ® p-NO2 C6H4NHCOCH3 ( C ) p-nitroacetanilide p-NO2 C6H4NHCOCH3 + H2O ® p- NO2 C6H4NH2 p-nitroaniline (D) isomer of (D) is m-nitroaniline
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