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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jun 2007 08:39:01 IST
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y=cos(pi/7).cos(2pi/7).cos(4pi/7)............
for n terms
2^n * sin(pi/7).y=2^n * sin(pi/7).cos(pi/7).cos(2pi/7).cos(4pi/7)....cos(2^npi/7)
2^n * sin(pi/7).y=2^n-1 * sin(2pi/7).cos(2pi/7).cos(4pi/7)....cos(2^npi/7)
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2^n *sin(pi/7).y = 2sin2^n(pi/7).cos2^n(pi/7)
2^n *sin(pi/7).y = sin2^n+1(pi/7)
y=[sin2^n+1(pi+7)]/2^n*sin(pi/7)
now as n -> inf.
lim y= (sin2^n+1(pi/7))
n->inf ---------------- ---->0
(2^n) .sin(pi/7)
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