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Discussion Response Post to: for students good in differentiation

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16 Jun 2007 16:29:47 IST

Subject: Re:for students good in differentiation

him26.89 (207)

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i think the base is x here.

so,here is the ans

qun can be written as

[log_elnx]/lnx

now derivative

[(1/lnx)(1/x) - (1/x)(loglnx)]/(lnx)²

putting x=e

lnx=1 log1=0

:. we get ans 1/e

this reply: 17 points (with 3 Olaaa!! Perrrfect answer.

in 4 votes ) [?]

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