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joyfrancis (1504)

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Olaaa!! Perrrfect answer. 236  [398 rates]

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Hi
 
The point where the pilot has to reach is 30 degrees east of north , now if we
take into account the wind blowing...if the plane heads in that direction only, he
would not land up in the desired spot.
 
Here is the solution.
Let the angle made by the plane be  degrees east of the line AB.
Net velocity in the x dir Vx=150cos(60-)
                                AB=500000m
 
                               ABsin30=Vx(t)
150cos(60-)t=250000.....(1)
velocity in the y direction Vy=150sin(60-)+20
                                   &ABcos30=250000root3=[150sin(60-)+20]t....(2)
equations 1 and 2 have 2 variables i.e  and t .
.: sin=1/15 and t=3000s=50min
 
 

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