Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: electrostatics
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10904him (114)

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Potential at the centre of 1st ring = kQ1/R + kQ2 / R(-/2)
Potential at the centre of 2ndt ring = kQ2/R + kQ1 / R(-/2)
p.d = k(Q2-Q1){1-1/ -/2 ) / R
=k(Q2-Q1)(-/2 -1) / -/2 R
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