tan(alpha) - tan ( beta)= tan ( A- B )(1+ tan(A) tan(B) As tan x is an inc curve always min val wud be wen A appraches B Hence min(f)= lim A->B tan(A-B)(tanAtanB + 1) mulyi div by A-B using lim x->0 tanx/x=1 and tanA=tanB min(f)= (A-B)(1+ tan(square) A) wich is eq to A-B * sec(square) A =A-B /cos(sq)A Sorry for joining a bit too late I was ignorant of the prob
Moderation Team
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