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[Post New]31 Jan 2007 10:53:50 IST
    Subject: Radius of curvature
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shakirshafi12 (881)

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Olaaa!! Perrrfect answer. 147  bad job dude!! I dont approve of this answer! 1  [222 rates]
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radius of curvature=ds/dQ
that is rate of change of path wrt to the rate of chane of angle of slope
dy/dx=tanQ here
and ds=sqroot((dx)^2+(dy)^2)
in shanti narayan they have discussed it in gr8 detail


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