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Discussion Response Post to: oxidation state

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arun-rashi (1128)

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the oxidation number of an element of an element in any species is equal to the charge which its atom appears to have acquired when all other atoms in the species are removed as ions.oxidation state can have +ive, -ive or 0 depending upon the state of combination in compound. Rules for counting e^-on atoms as they r being removed as ions1.e- divided equally when they r shared bet^n like atoms so none of the atoms aquire charge e.g H₂Has 0 oxi state similarly in elemental form v have 0 OXI St 2.e- shared bet ^n unlike atms r counted with more electronegative atom e.g HCl,Cl more electronegative than H hence acq -1 &H acq +1.3. OXI St for O IN OXIDESis -2 ,PEROXIDES-1,for H is +1,F-1,IONS has oxi st equal to charge eg Na+ has +1Al+3 HAS +3.Applying them if v calculate oxi st of underlined atom in an comp (which is neutral )KMnO₄say it is xso 1+x+4*(-2)=0 so x is +7

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