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priyesh (1605)

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Olaaa!! Perrrfect answer. 259  [414 rates]

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here's a short soln. i hope this helps
equation for small block
(/2)mg = mas    (as = acceleration of small block w.r.t ground)
=> as = (/2)g   (towards left)
similarly equation for larger block
(M+m)g - (/2)mg  = MaL   (where aL = acceleration of larger block w.r.t ground )
=> aL = [(/2)(m/M)]g + g   (towards left)
 now asL = as - aL =  (/2)g - ( [(/2)(m/M)]g + g )    (asL = acceleration of small block w.r.t bigger block)
 => asL = [{g(M+m)}/2M] (towards right)
now
l = 1/2 * asL * t^2
l = 1/2 * [{g(M+m)}/2M] * t^2
t^2 = 4Ml/[g(M+m)]
t = sqroot(4Ml/[g(M+m)])
hope you understod
cheers
 

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