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arun-rashi (1128)

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Ans.1( i) 1 mole =6.023 *10²³(N ) molecules, no of e in 1 molecule of CH4=6+4= 10 So in 1 mole =N *10=6.023*10²⁴e (ii) (a)C-14 contain 14-6 neutrons in 14000mg so in 7mg there r 8* N *7/14000=2.401*10²¹NEUTRONS (b)mass of this much no of neutrons =1.65*10^-27 kg *2.401*10²¹=4.03*10^-6 kg (iii) (a )1 mole of NH3 =N molecules= 17 g=7+3*N protons so no of protons in .034g =N*10*.034/17=1.203*10²²(b)so mass of this much no of protons =1.673*10^-27 *1.203*10²²=2.01*10^-5 kg There is no effect of temp & pressure bec e ,mass, mole r not temp or pressure related terms Answers to Qno 2,3,4 already given in previous message.

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