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®µD®A (2710)

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OK can you explain this ?

 

a=b=c=racpi{4}

 

rac{	an(a+b-c)}{	an(a-b+c)}=rac{	anleft(rac{pi}{4}ight)}{	anleft(rac{pi}{4}ight)}=1

 

And,

 

rac{	an c}{	an b} = 1

 

But, sin2a+sin2b+sin2c=1+1+1=3


[IMG]http://alt1.artofproblemsolving.com/Forum/latexrender/pictures/0/6/3/0638cc54ee34d87aa803d78fe3ec072aa8749bf5.gif[/IMG] :)
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