Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Projectile motion : Question from IAPT exam
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10904him (114)

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Initial velocity = -vcos$
Thus in time period 2vsin$/g
a=0.8 m/s sq horizontal
s=0 --> velocity =0
u=at
v cos$ =0.8.2vsin$/2g
tan $ =5g/4 Ans

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