Any P and C questions?
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@NugoRama dunno if it is correct ... i posted the same reply and someone told me that it was incorrect few months ago. so better this way..
For n=1
For those who want to know
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![\Gamma\ 1=\int_0^{\infty}e^{-x}x^{1-1}dx\\\\=\lim_{b\to\infty}\int_0^{b}e^{-x}\\\\=\lim_{b\to\infty}[-e^{-x}]_0^b\\\\=\lim_{b\to\infty}(-e^{-b}+e^0)=0+1=1](http://alt1.artofproblemsolving.com/Forum/latexrender/pictures/7/7/d/77d2aac46f521b8521c2a0914bab52ec28a49940.gif)








