E-Store
a ball is dropped from a height. if it takes 0.200s to cross the last 6.00m before hitting the g
|
| Forum Index -> Mechanics -> View Full Question |
|
| Author | Message | |||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
|
let the intial velocityof th eball b4 the last 6m be =U a=10 s=6 t=0.2 s=ut+1/2at^2 6=0.2 U+1/2*10*0.2*0.2 0.2U=5.8 U=29 now consider the journey from rest to this height V=29m/s U=0 a=10 v^2=u^2+2as 29*29=2*10*s therefore s= 29*29/20 = 42.05 thereforethe total height = 42.05+6 = 48.05m |
|||||||||||||
| Like 0 people liked this | ||||||||||||||
|
|
||||||||||||||
Free Sign Up!
Preparing for IIT-JEE ?
Arihant Revision Package for IIT JEE - Books, Practice Tests + Rank Predictor
@ INR 1,995/-
For Quick Info
|
|
|
|
|
| 35,229,755 Engineering Questions Attempted |
6,69,530 Visitors Monthly |
79 Engg. Exam Covered |
437 Students Currently Online |
Connect with Us  |
 |
Vriti Communities
Privacy Policy © Vriti 2011