pls solve hcv ques.23 exercise newton,s laws of motions.................................

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Akshay (1451)

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When one of the blocks is held, the string goes slack. So the tension in the string becomes zero. So the other block will movupward under the influence of gravity. It's basically uniformly retarded motion, while the

So, m1 , m2 be the masses. Then, acceleration of each block is thus {(m2-m1)/(m1+m2)}g=a

Now, the upper block has a velocity of 2a after 2 secs, hence, the the time taken to reach the maximum height in its motion under gravity

is given by 2a-gt=0

t=2a/g.

It is at this point that the system regains its tension

Solving for t it comes out to be 2/3 seconds.

Finally I reveal myself...

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