Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: newtons laws of motion
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ramyani chakrabarty (3105)

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The man exetrs a force F (say) so that his effective wieght is (mg - F) as shown by the weighing machine.(m = mass of the man)

weight of the box + +effective wieght of man = force applied by man
30g + 60g - F= F
or F=45kg

thus the weight shown by the machine = mg - F=15 kg
now if u apply force F reading is 15kg. To get correct wiehtg (60 kg) we must apply 4F=4*45kg=180kg=1800N.

there is also another method.

NIT silchar electrical engineering
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