7. 0.15, 0.015, 0.0015, ... 20 terms. find sum of G.P. ans is 1/6[1-(0.1)^20] . wrking

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Blazing goIITian

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$S_n=\frac{a(1-r^n)}{1-r}$

$S_{20}=\frac{0.15(1-0.1^{20})}{1-0.1}$ $=\frac{1.5(1-0.1^{20})}{9}$ $=\frac{(1-0.1^{20})}{6}$

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