differential calculus

Discussion Response Post to: differential calculus

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Blazing goIITian

total posts: 302
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I actually cal. this question;

but unfortunately my net connection went off and i lost it.

I am not willing to write all that again as it is very time consuming.

But in brief :

(x1, y1) lie on the curve.

So, eqn. of tangent will be:

2 - y1 = (6x1²) / ( 2y1 - 4) ( 1 -x1)

With the help of this and the eqn. of the curve, u get x as -1 and 2.

Solve further as i earlier posted.

Note the not : Numbers in life can't be chased.

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