current electricity
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let dere be a total of n cells.................... 2 cells have emf in opp directiond remaining n-2 have in another direction..........ok. total current thru the circuit will be...........total v/ total r total r in series combination of cells will be nr.... total V =( n-2)E - nE.. total current is {(n-2)E - nE}/ nr now as such the net potential difference across the terminals of any cell is E- ir.. but in dis case more no of cells have dere emf in opp dir as compared to the direction of of emf of cell A or B..... dat means the cell is getting charged up.......... so V= E+ir therefore V=2E(1- 2/n)............... good luck rate if useful......... |
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Dont walk as if u rule the world....... walk as if u dont care who rules the world!!!!!!!! |
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