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kghedriu (2343)

Blazing goIITian

Olaaa!! Perrrfect answer. 425  [534 rates]

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well.....
put tanx= t^2
  => sec^2x dx = 2tdt
  => (1+ tan^2 x) dx= 2t dt
  => (1+t^4) dx = 2t dt
  => dx = 2t/(1+t^4) dt
.:
[ ] (tan x)1/2 dx = [ ] 2t^2/(1+t^4) dt
 
now integrate using standard formulae....
 
Goutham Harsha (I find bliss in ignorance [^_^] )
 this reply: 2 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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