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a 2mev proton (mass=1.6 *10^-27 kg) is moving perpendicular to a uniform magnetic field of 2.5 t.
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First of all find the velocity from the given energy of the proton using 1/2mv2 = Energy given then Force on proton is give by = q. (v x B) = qvB as angle btw velocity and magnetic field is 90 q = e and find the answweer good luck |
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