Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: given log2= 0.301 evaluate log 1000/256
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Priyesh (1601)

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log(1000/256)= log1000 - log256 = log1000 - 8log2   (since 256 = 2^8 hence log256 = log2^8 = 8log2 (since loga^b = bloga))

= 3 - 8 * .301= 3 - 2.408 =  0.592


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