IIT JEE , AIEEE Forum - Physics , Mechanics

waterdemon

No problems Maverick just wanted to tell you that you were going wrong .

Hey Karhtik just saw that you had replied , so am editing watch the

answer I have solved it.

So here is the solution

For pire rolling to take place

V = R

₀ = Angular Velocity of centre of mass of sphere about point O.

₀ = V/4R = R / 4R = /R

₀ = /R

d₀/dt = 1/4 [ d/dt ]

₀ = /4

For pure rolling

= a / 4

a = (gSin) / [1+ I/MR²]

Since I = 2MR²/5

a = 5gSin/7

₀= 5gSin/28R

For Small oscillations

Sin =

₀ = (-5g/28R)

T = 2 28R/5g

Hence the answer .

Hope you got it Maverick.

Rate if you liked it.

Cheers !!!!!!!!!!!!!!