IIT JEE , AIEEE Forum - Physics , Mechanics

sankydreams

let time taken by truck in moving this dist = t
this will also be the time period of the projectile
horizontal dist covered by ball will also be 58.8
let s = 58.8

let initial horizontal velo of truck = u
let speed with which the ball is thrown = v at an angle A with horizontal

initial vertical velo = vsinA
constant horizontal velo = vcosA + u

t =s/ (vcosA + u) (horizontal motion of projectile)
on solving this eqn we get
u = (s - tvcosA ) / t .........(1)

time period of projectile = t= (2vsinA)/g........(2)

s= ut + + 1/2at^2 (horizontal motion of truck)
in this eqn put value of u from (1) and value of t from (2)
u will get tanA = g/a = 9.8/14.7 = 1/3

find other things on solving further
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