please solve: minimum force to pull up a mass on incline (with a spring)

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rumki chakraborty (41)

Cool goIITian

total posts: 41
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From the figure itself, it's clear that kx=T.

Forming the different equations, we have

$Mg\;-\;T\;=\;Ma$

Since the block just has to move up, i.e., it just has to start its motion, so we'll consider the acceleration to be zero.
So, now we have

$Mg\;=\;T$

Similarly, we'll get the other equation as

$T\;-\;mg\;sin\;37\;-\;\mu mg\;cos\;37\;=\;0$

T=Mg (Just shown). Put the different values and get the answer as:-

$M\;=\;\frac{6}{5}m$

but the answer given is : 3m/5.

this problem is given at four locations and all with the same answer: 3m/5

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