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Discussion Response Post to: qudratic 78

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Titun (1467)

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total posts: 374
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4^x- 3^{x - 1/2}= 3^{x + 1/2}- 2^{2x - 1}

4^x + 2^{2x - 1} = 3^x [

3 + 1 /

3 ]

2 ^2x( 1 + 1/2 ) = 3^x. 4 /

2 ^2x . 3 / 2 = 3^x. 4 /

2 ^{2x - 3}= 3 ^{x - 3 / 2}

4 ^{x - 3 / 2}= 3 ^{x - 3 / 2}

(4 / 3) ^{x - 3 / 2}= 1

x - 3/2 = 0

x = 3 / 2

Ans: x = 3 / 2

Cheers !!!!!

You never know what is enough till you know what is more than enough. Titun

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