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Bipin Dubey (13469)

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I=\int_{.}^{.}\frac{3+2cosx}{(2+3cosx)^{2}}dx

 

I=\int_{.}^{.}\frac{3(sin^{2}x+cos^{2}x)+2cosx}{(2+3cosx)^{2}}dx

 

I=\int_{.}^{.}\frac{cosx(2+3cosx)+3sin^{2}x}{(2+3cosx)^{2}}dx

 

I=\int_{.}^{.}\frac{(2+3cosx)d(sinx)-(sinx)d(2+3cosx)}{(2+3cosx)^{2}}dx

 

I=\int_{.}^{.}d\left( \frac{sinx}{2+3cosx}\right)

 

I=\frac{sinx}{2+3cosx}+c

 

 


Bipin Kumar Dubey Chemical Dept. IIT Kharagpur
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