period of function
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If the period of a function g(x) is T , then the period of the function g(ax) is T/a (where 'a' is not equal to zero.) The period of the function sinx is 2 . Therefore, period of the function sin (2x/3) is 2 / (2/3) i.e 3 ![]() Similarly, period of the function sin (3x/2) is 2 / (3/2) i.e 4 /3Therefore, period of the function, f (x) = sin (2x/3) + sin (3x/2) will be the L.C.M of the periods of the functions sin (2x/3) and sin (3x/2) i.e L.C.M of 3 and 4 /3 i.e 12 ![]() Ans: 12 ![]() Cheers ! |
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/ (2/3) i.e 3 







