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Discussion Response Post to: eudiometry

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deepak_agarwal (551)

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eudiometry ques are long and u need to follow each step and thts it..they r nt tough.....

from first line we know total moles of all three gases and their total pressure so we can get V/T ratio easily and we get the eqn

x+y+z=.000522 where x y z are moles of h2,o2,n2 respectively...

now after the gaseous mxture was frst burnt over filament it was returned to same tube after frozen water seperated....now since 1 mole of o2 consumes 2 moles of h2 tht implies y moles of o2 takes 2y moles and hence h2 left is (x-2y)(we have taken o2 limited becoz read next line of ques xcarefully...o2 is added and again burn..so h2 must be there)....

z+(x-2y)=14.3mm * (V/R*T)...V/T we know from above

now extra o2 was added and we can get tht xtra o2 by simple(32.9-14.3)*(V/R*T)...and from this u can get how much h2 was consumed so u get to know how muc is left...so u get third eqn....

fine...

a 2nd year IIT DELHI student, doing B.Tech in chemical engineering

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