taking logs on both sides we have.....
(logy-logz)logx + (logz-logx)logy + (logx-logy)logz = log1=0
=> let logx=a logy=b logz=c
=> we have(b-c)a + (c-a)b + (a-b)c = 0
=> opening the brackets we get.... ab-ac+bc-ab+ac-bc=0
=> we get 0=0
HENCE PROVED....!!!!!!!
if u lke my reply plzzz rate meeee....
Moderation Team
![[Post New]](/templates/default/images/icon_minipost_new.gif){kind=icon}
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
14
