when x tends to zero (sinx)/x tends to one from left
so ans. is n-1
and joyfrancis your mistake is in this step
=
[x]
[0] [n*(1 - (x
2 / 3!) + (x
4 / 5!) - (x
6 / 7!).....inf terms)]
put x = 0
you will get [n] by putting x = 0 only when the terms would have been finite
but in this case since the terms are infinite hence all the terms after 1 although tend to zero(remember they only tend to zero and do not become equal to zero) but due to infinite terms thier sum will not be zero.
I hope i made myself clear enough
do as if any doubt