{x+1}+2x=4[x+1]-6 {}=fractional part..[]=integral part...pls solvve..rates assured.

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In many of these problems, a useful strategy is try to obtain an equation like {x} = "something" and exploit the fact that 0<={x}<1.

Here LHS = {x} + 2x = {x} + 2([x]+{x}] = 2[x] +3{x}

So the equation can be written as 3 {x} = 2[x] - 2. or $\{x\} = \frac{2[x]-2}{3}$

So {x} is a rational number of the form n/3 where n is a non-negative even integer. So n = 0 or 2.

n = 0 gives x =1.

n = 2 gives 8/3

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