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Titun (1467)

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1st problem.

0 cos - 1 x

Therefore,  0 cos -1 x 1
                0 cos -1 x 2
                         .
                         .
                         .
                         .
                         .
              0 cos -1 x n

Therefore,

cos -1x1 + cos -1 x2 + ................ cos -1 xn n

The equality holds only when

cos -1 x1 = cos -1 x2 = .............................. = cos -1 xn =
i.e x1 = x2 = ..........................................= xn = - 1

So,
x12 + x22 + ............................+ xn2 = 1+1+ .............n times = n

2nd problem.

- / 2  sin  - 1 x /2

Therefore,  - /2 sin -1 x 1 /2
                - /2 sin -1 x 2 /2
                         .
                         .
                         .
                         .
                         .
             -/2 sin -1 x 2n /2

Therefore,

sin-1x1 + sin -1 x2 + ................ sin -1 x2n 2n . /2 = n

The equality holds only when

sin -1 x1 = sin -1 x2 = .............................. = sin -1 x2n = /2
i.e x1 = x2 = ..........................................= x2n =  1

So,
x1 + x2 + ............................+ x2n = 1+1+ .............2n times = 2n

Cheers !!!!!

 

 

You never know what is enough till you know what is more than enough. Titun
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