INVERSE TRIGNO-ans req soooooooooooooooooonnnnnnnnnnnnnnnnnnnn
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1st problem. 0 cos - 1 x ![]() Therefore, 0 cos -1 x 1 ![]() 0 cos -1 x 2 ![]() . . . . . 0 cos -1 x n ![]() Therefore, cos -1x1 + cos -1 x2 + ................ cos -1 xn n![]() The equality holds only when cos -1 x1 = cos -1 x2 = .............................. = cos -1 xn = ![]() i.e x1 = x2 = ..........................................= xn = - 1 So, x12 + x22 + ............................+ xn2 = 1+1+ .............n times = n 2nd problem. - / 2 sin - 1 x /2Therefore, - /2 sin -1 x 1 /2- /2 sin -1 x 2 /2. . . . . - /2 sin -1 x 2n /2Therefore, sin-1x1 + sin -1 x2 + ................ sin -1 x2n 2n . /2 = n ![]() The equality holds only when sin -1 x1 = sin -1 x2 = .............................. = sin -1 x2n = /2i.e x1 = x2 = ..........................................= x2n = 1 So, x1 + x2 + ............................+ x2n = 1+1+ .............2n times = 2n Cheers !!!!! |
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You never know what is enough till you know what is more than enough. Titun |
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cos - 1 x 








