act the ans of this ques is zero but acc to me it shud be 5!/log5
|
| Forum Index -> Differential Calculus -> View Full Question |
|
| Author | Message | |||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
|
Applying l-hospital's rule lt x-> infinity 5x4 / 5x log(5) = (5/log(5)) ( lt x-> infinity x4 / 5x ) Apply l-hospital's rule again and again and finally you will get = 0
|
|||||||||||||
The best changes often start as a single, simple thought. Think big, and discover the ways to make your dreams real. |
||||||||||||||
| Like 0 people liked this | ||||||||||||||
|
|
||||||||||||||













