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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Aug 2007 13:46:36 IST
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product of roots
a^3 = 1
therefore a = 1, w, w^2
also we know that 1 + w + w^2 = 0
sum of roots
a^2 + a = -p/3
substitute a^2 by 1/ a ( as acube = 1) and we get
(1+ a^2 ) / a = - p/3
as p>0
left hand side can only be -ve when a = w out of 1 , w and w^2
thus
a^2 + a = - p/3
==>> w^2 + w = -p/3
- 1 = -p/3 .. (as w^2 + w + 1 = 0)
p = 3
PLZ RATE :)
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* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
* Your friendly neighborhood spideyunlimited |
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