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biki (1628)

Blazing goIITian

Olaaa!! Perrrfect answer. 288  [382 rates]

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when the wedge is moved with accl^n a the body of mass m experieces a psuedo force ma towards opposite direction of the motion of wedge (as shown in figure).
Now resolving the forces as shown in figure...
we get ( for the body to remain at rest)
ma.cos = mg.sin
or a = g.tan ____________(1)
This is the accl^n to be provided to the wedge so that the block doesnot fall.
So again from figure we get that the force which the block gives the incline perpendicularly = ma.sin + mg.cos 
This force = force given by incline on the block....( from Newton's 3rd Law)
So reqd. force = ma.sin + mg.cos
                     = mg.tan.sin + mg.cos .........[ by (1) ]
                     = mg.(sin2/cos) + mg.cos
                     = mg.(sin2 + cos2) / cos
                     = mg / cos...
 


salman khan
 this reply: 12 points  (with Olaaa!! Perrrfect answer.   in 3 votes )   [?]
 
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