Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: PLEASE HELP ME TO SOLVE EQUIVALENT RESISTANCE PROBLEM
Forum Index -> Electricity -> View Full Question Email  
Author Message
Nehal Wani (283)

Hot goIITian


Nehal Wani's Avatar

total posts: 166    
Offline

 

This Circuit Can Be Broken As:

1 and 2 are in series. Resultant 9: 2R

6 and 7 are in series. Resultant 10: 2R

9 and 3 are in parallel. Resultant 11:2R/3

10 and 3 are in parallel. Resultant 12:2R/3
11,4 and 5 are in series. Resultant: 13:8R/3
13 and 12 are in parallel. Resultant: 14:8R/15
Therefore, Resistance across A and B is 8R/15

0 people liked this
 
Free Sign Up!

Preparing for IIT-JEE ?

Arihant Revision Package for IIT JEE - Books, Practice Tests + Rank Predictor


@ INR 1,995/-

For Quick Info

Name

Mobile No.

Sponsored Ads