let A=(-3,4);B = (1,6);C = (-2,3).......... we know that circumcentre is the pt of intersection of the perpendicular bisectors......... let,D be the midpoint of side BC............ so, D = (-1/2,9/2) now slope of the perpendicular bisector*slope of BC = -1.................... so get the equation of the P.B.......... similarly take another side n its midpt. find tht P.B. intersection of these 2 P.B.'s is the circumcentre...................
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