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sen_holmes (23)

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Olaaa!! Perrrfect answer. 3  [7 rates]

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total posts: 42    
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i think the ans ia a)
 
bcoz .........
let mass of a=m1
let mass of b=m2
now initial vel of both=u
final vel of both=0
change in k.e =change in p.e
therefore
for a
1/2*m1*(-u^2)=-m1*g*h1                           h1=dist travelled by a
u^2/2=gh
h=u^2/2g
 
for b
1/2*m2*(-u^2)=m2*g*h2                             h2=dist travelled by b
 
simplifying
 
h2=u^2/2g
 
therefore h1=h2
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