The underlined carbon has double bond on either side, i.e., one sigma and one pi bond. Hence the hybid state of the carbon will be sp, because in this hybridisation carbon can form one sigma bond on either side. The pi bonds are formed using the unhybridised p orbitals. Refer to structure of allene.
Moderation Team
![[Post New]](/templates/default/images/icon_minipost_new.gif){kind=icon}
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
243
