IIT JEE , AIEEE Forum - Physics , Mechanics

shyam_nair_s

As u said i have solved it in a lucid manner.

Look this is the perfect solution coz there?s a little typing mistake in first line of previous ans

Here since the body is undergoing circular motion.

Initially it is having only radial acceleration ( a_r) ?that?s the first part.

And in the second part that u have asked the body is having a tangential acceleration a_t along with radial acceleration as given in the question.

So a_t = la and a_r = w²l here take a as alpha (angular acc)

Hence for the particle performing uniformly acc circular motion,

umg = m a_resultant

umg = m [( a_r) ²+ (a_t) ² ] ^1/2

ug = [( w²l) ² + (ra)² ] ^1/2

w4 l² + r² a² = u² g²

w⁴ = [u²g²/l² minus a² ]

w= [u²g²/l² minus a² ]^1/4-------------------ANS

Yaar I?m very much sure u must have got in now.

Best of luck!