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[Post New]12 Aug 2007 08:38:28 IST
    Subject: Magnetic field due to a current
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krishna.gopal (2917)

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Olaaa!! Perrrfect answer. 469  bad job dude!! I dont approve of this answer! 2  [759 rates]
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B1 = (mu_not)*i/(2*pi*r)

If you solve for field because of finite wire

B2 = ((mu_not)*i/(2*pi*r))*((l/2)/sqrt((l/2)^2+d^2))
for B2 tp be 0.99 B1

l/(2*sqrt((l/2)^2+d^2))=0.99
Sollve to get d/l
Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi
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